![]() Using the inertia tensor, I can easily find the moment of inertia of this rod, in the direction of the axis. Moment of Inertia I of a rod of mass M about an axis passing through centre of mass and perpendicular to its length L is given by, I M×(L2 / 12 ) 2g-cm2. Frame Axyz, the object coordinate system, is. ![]() In this example, the given angle is /4 / 4, but I'm looking for a general solution. Recitation 6 Notes: Moment of Inertia and Imbalance, Rotating Slender Rod. The moment of inertia of a rod may be defined as the summation of the products which we get from the whole mass of every attached element of the rod and this. \): Moment of Inertia of a Uniform DiskĪ thin uniform disk of mass \(M\) and radius \(R\) is mounted on an axle passing through the center of the disk, perpendicular to the plane of the disk. The rod is rotating about this axis, and I'm supposed to find the magnitude of the angular momentum and the torque. ![]()
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